The code was very janky, but it worked - eviltoast
  • marcos@lemmy.world
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    8 months ago
    (+x) % 2 == 0
    

    If you forget for a second it’s Javascript, the language will turn back and bite you.

      • mindbleach@sh.itjust.works
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        8 months ago

        JS is a language where [1,2,11].sort() returns [1,11,2].

        And if you use a variable instead of a bare array, half the functions are side-effectful, as determined by coin toss.

        And if you try declaring that variable with new Array(3).map() then it will ignore all 3 indices, because undefined is real enough to be enumerated, but not real enough to be iterated, because, and I cannot overstress the importance of this principle in Javascript, go fuck yourself. Go fuck yourself is why.

      • marcos@lemmy.world
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        8 months ago

        This evaluates to NaN for some reason:

        '10' % 0
        

        Since JS doesn’t really differentiate strings from numbers, except on the places it does, it makes sense to make sure you are working with numbers.

        • FiskFisk33@startrek.website
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          8 months ago

          Oh right that. I guess I was visualizing a scenario where you already checked for it being a number, such as a Number.isInteger(x)

          also, that suprises me a lot, you’d think this is one of the places where it treats stuff as numbers