Heh - eviltoast
  • photonic_sorcerer@lemmy.dbzer0.com
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    1 year ago

    Yes, of course. Coloumb and Maxwell had no idea about QM when they were developing their ideas. Not to mention that these higher-order abstractions are just as valid as QM (up to a point, but so is QM). Depening on the application, you’d want to use a different abstraction. EM is perfect for everyday use, as well as all the way down to the microscale.

    My point is that EM is explained by QM, and therefore supercedes it. You could use QM to solve every EM problem, it’d just be waaaaay too difficult to be practical.

    • scubbo@lemmy.ml
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      1 year ago

      I feel like you’re using “supercede” differently to the rest of us. You’re getting a hostile reaction because it sounded like you’re saying that EM is no longer at all useful because it has been obsoleted (superceded) by QM. Now you’re (correctly) saying that EM is still useful within its domain, but continuing to say that QM supercedes it. To me, at least, that’s a contradiction. QM extends EM, but does not supercede it. If EM were supercedes, there would be no situation in which it was useful.

    • SuckMyWang@lemmy.world
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      1 year ago

      Guys guys, yesterday I ate some hot wings and then shit myself on the way to the toilet 🤣💪💯

      Also can you really solve all em equations with qm? I always thought the laws broke down from one to the other? So you’re saying going from em to qm the laws break down but going from qm to em the laws hold up?