Code interviews for a PHP developer roles - eviltoast
  • Naich@lemmings.world
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    8 months ago

    Want to print out all odd numbers from 1 to 100? Easy:

    for(_=[];_<+!![]+""+[]*[]+[]*[];_++)(_%+(!![]+!![])?console.log(_):[]);

    • Naich@lemmings.world
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      8 months ago

      Actually, I prefer this one: for(_=[];_<+!![]+""+[]*[]+[]*[];_++%+(!![]+!![])?[]:console.log(_));

      • Naich@lemmings.world
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        8 months ago

        Or this one without the “undefined” when run in a browser console:

        for(_=[];_<+!![]+""+[]*[]+[]*[]-!![]-!![];_++%+(!![]+!![])?[]:console.log(_));_+!![]

          • Naich@lemmings.world
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            8 months ago

            _ is a variable name, [] becomes 0 when converted to an integer, !![] becomes 1. The + “” + means that the integers 1, 0, 0 get converted to a string - “100”, which gets converted back to an integer because it’s in the for loop. And there’s various other horrible conversions going on to make it all work.