❄️ - 2023 DAY 10 SOLUTIONS -❄️ - eviltoast

Day 10: Pipe Maze

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  • mykl@lemmy.world
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    11 months ago

    Dart

    Finally got round to solving part 2. Very easy once I realised it’s just a matter of counting line crossings.

    Edit: having now read the other comments here, I’m reminded that the line-crossing logic is actually an application of Jordan’s Curve Theorem which looks like a mathematical joke when you first see it, but turns out to be really useful here!

    var up = Point(0, -1),
        down = Point(0, 1),
        left = Point(-1, 0),
        right = Point(1, 0);
    var pipes = >>{
      '|': [up, down],
      '-': [left, right],
      'L': [up, right],
      'J': [up, left],
      '7': [left, down],
      'F': [right, down],
    };
    late List> grid; // Make grid global for part 2
    Set> buildPath(List lines) {
      grid = lines.map((e) => e.split('')).toList();
      var points = {
        for (var row in grid.indices())
          for (var col in grid.first.indices()) Point(col, row): grid[row][col]
      };
      // Find the starting point.
      var pos = points.entries.firstWhere((e) => e.value == 'S').key;
      var path = {pos};
      // Replace 'S' with assumed pipe.
      var dirs = [up, down, left, right].where((el) =>
          points.keys.contains(pos + el) &&
          pipes.containsKey(points[pos + el]) &&
          pipes[points[pos + el]]!.contains(Point(-el.x, -el.y)));
      grid[pos.y][pos.x] = pipes.entries
          .firstWhere((e) =>
              (e.value.first == dirs.first) && (e.value.last == dirs.last) ||
              (e.value.first == dirs.last) && (e.value.last == dirs.first))
          .key;
    
      // Follow the path.
      while (true) {
        var nd = dirs.firstWhereOrNull((e) =>
            points.containsKey(pos + e) &&
            !path.contains(pos + e) &&
            (points[pos + e] == 'S' || pipes.containsKey(points[pos + e])));
        if (nd == null) break;
        pos += nd;
        path.add(pos);
        dirs = pipes[points[pos]]!;
      }
      return path;
    }
    
    part1(List lines) => buildPath(lines).length ~/ 2;
    part2(List lines) {
      var path = buildPath(lines);
      var count = 0;
      for (var r in grid.indices()) {
        var outside = true;
        // We're only interested in how many times we have crossed the path
        // to get to any given point, so mark anything that's not on the path
        // as '*' for counting, and collapse all uninteresting path segments.
        var row = grid[r]
            .indexed()
            .map((e) => path.contains(Point(e.index, r)) ? e.value : '*')
            .join('')
            .replaceAll('-', '')
            .replaceAll('FJ', '|') // zigzag
            .replaceAll('L7', '|') // other zigzag
            .replaceAll('LJ', '') // U-bend
            .replaceAll('F7', ''); // n-bend
        for (var c in row.split('')) {
          if (c == '|') {
            outside = !outside;
          } else {
            if (!outside && c == '*') count += 1;
          }
        }
      }
      return count;
    }