As the title says, I just started with linux mint and am falling in love with bash scripts 😍 Actually I’m not sure if it’s considered a script, but I want to delete the last 2 files in all subfolders in a folder. So far I’ve (after great effort) got the terminal to list the files, but I want to delete them. Here is how I get them listed:
for f in *; do ls $f | tail -n 2; done
All their names come satisfyingly up in the terminal. Now what? I tried adding | xargs rm but that didn’t delete them. I also tried something with find command but that didn’t work either. Some folders have 3 items, so I want to delete #2 and 3. Some folders have 15 items so I want to delete #14 and 15. Folders are arranged by name, so it’s always the last 2 that I want to delete.
It’s frustrating to be sooooo clooooose, but also very fun. Any help is appreciated!
EDIT: Thanks for the awesome help guys! The next part of this is to move all the .html files into one folder (named “done”), prepending their name with an integer. So far I got:
n=1; for f in *; do find ./"$f" -type f | sort | xargs mv done/"$n$f"; n=$((n+1)); done
but that is… not really doing anything. The closest I have gotten so far is some error like
mv: Missing destination file operand
Any help is again appreciated!
It won’t work the way you need it to as is, since the find command will first move all of those files together into the same folder, and if there are similar names between folder, like:
Then it will throw errors and/or overwrite files.
I’m at work so I can’t loom at this right now but I’ll look at it later when I get home.
Yea, I just came back to say this. Since cp overwrites by default (I tried copying first before trying moving) and each folder has files named index001 index002 etc then then folder where they all go has only ONE of index001.html, ONE of index002.html etc. So I think what I need to do is find each html file, rename it with a unique integer in front of the name, move it to the common folder.
Okay, took me awhile to write everything up. The script itself is pretty short, but it’s still much easier to do in a script than to try to make this a one line command.
I tested this creating a top level directory, and then creating three subdirectories inside it with a different number of html files inside those directories, and it worked perfectly. I’m going to break down exactly what’s going on in the script, but do note the two commented commands. I set this script up so you can test it before actually executing it on your files. In the breakdown of the script I’m going to ignore the testing command as if it were not in the script.
The script:
#! /bin/bash # script to move all html files from a series of directories into a single directory, and rename them as they are moved by adding a numeric indicator # to the beginning of the filename, while keeping files of the same folder grouped. fileList="$(find ~/test -name '*.html' | sort)" num=1 while IFS= read -r line; do pad="$(printf '%03d' $num)" #The below echo command will test the script to ensure it works. #The output to the terminal will show the mv command for each file. #If the results are what you want, you can comment this line out to disable the command, or delete it entirely. echo "mv $line ~/done/"$pad${line##*/}"" #This commented out mv command will actually move and rename all of the files. #When you are certain based on the testing that the script will work as desired #uncomment this line to allow the command to run and move & rename the files. # mv $line ~/done/"$pad${line##*/}" ((num++)) done<<<"$fileList"
The breakdown of the script is in the reply comment. Lemmy wouldn’t let me post it as one comment.
The breakdown:
#! /bin/bash
- This heads every bash script and is necessary to tell your shell environment what interpreter to use for the script. In this case we’re using/bin/bash
to execute the script.fileList="$(find ~/path/to/dir/with/html/files -name '*.html' | sort)"
- What this command is doing is creating a variable calledfileList
using command substitution. Command substitution encloses a command in"$()"
to tellbash
to execute the command(s) contained within the substitution group and save the output of the command(s) to the variable. In this case the commands are afind
command piped into asort
command.find ~/path/to/dir/with/html/files -name '*.html' | sort
- So this is the command set that will execute and the output of this command will be saved to the variablefileList
.num=1
- Here we’re creating a variable callednum
with a value of1
. This is for adding sequential numbers to the files as they are moved from their source directory to the destination directory.while IFS= read -r line; do
- This script uses awhile
loop to process each item saved to thefileList
variable. Within thewhile
loop, the moving and renaming of the files will take place.pad="$(printf '%03d' $num)"
- This is another variable being created using command substitution. What the command in the substitution group does is take thenum
variable and pad it with zeroes to be a three digit number.printf '%03d' $num
- This is the command that runs inside the substitution set.mv $line /path/to/dest/"$pad${line##*/}"
- This command actually moves and renames the file.((num++))
- Is a nice easy way to increment a number variable inbash
done<<<"$fileList"
- Is three parts.done
indicates the end of the while loop.<<<
is forheredoc
, which is a bash utility that allows you to pass a multiline chunk of text into a command. To pass a variable into a command withheredoc
you need to use three less than symbols (<<<
). Finally, is the variable holding the chunk of text we want fed into thewhile
loop, which is thefileList
variable (double quoted to insure proper expansion ignoring spaces and other nonstandard characters).And that’s the script! Let me know how it works for you.
Agree. I think for that a bash script will be a better approach. I’ll be off work in a few hours. I’ll take a look then.